1/x+9/x^2=-1

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Solution for 1/x+9/x^2=-1 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x+9/(x^2) = -1 // + 1

1/x+9/(x^2)+1 = 0

x^-1+9*x^-2+1 = 0

t_1 = x^-1

9*t_1^2+1*t_1^1+1 = 0

9*t_1^2+t_1+1 = 0

DELTA = 1^2-(1*4*9)

DELTA = -35

DELTA < 0

x belongs to the empty set

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